16F877單片機(jī)與PC機(jī)通訊的源程序
推薦 + 挑錯(cuò) + 收藏(0) + 用戶評(píng)論（0）
elecfans.com- 16F877單片機(jī)與PC機(jī)通訊的源程序.rar
;****************************************
;*?????? 單片機(jī)與PC機(jī)通訊的源程序?????? *
;****************************************
???????;※※※※※※※※※※※※※※※※※
???????;※資料提供：上海齊濟(jì)電子有限公司※
???????;※聯(lián)系電話：21-65630199???????? ※
???????;※※※※※※※※※※※※※※※※※
;單片機(jī)與PC機(jī)通訊的源程序（詳細(xì)）??
;單片機(jī)的程序
LIST????? P=16F876
#INCLUDE??? P16F876.INC
CBLOCK 0X24
COUNT??
TEMP
ENDC
????? ORG?? 0X0000
????? NOP
START?? GOTO?? MAIN
????? ORG????? 0X020
MAIN?? MOVLW?? 0X30??????????? ；將RAM單元初始化
????? MOVWF?? FSR
????? BCF????? STATUS，RP0
????? MOVLW?? 0X22
????? MOVWF?? COUNT
INTRAM?? MOVF?? COUNT，0
????? MOVWF?? INDF
????? INCF????? COUNT，1
????? INCF????? FSR，1
????? BTFSS?? FSR，7
????? GOTO?? INTRAM
????? BANKSEL?? TXSTA???????? ；波特率設(shè)置為9 600 bps
????? MOVLW?? 0X19
????? MOVWF?? SPBRG???????? ；異步高速方式
????? MOVLW?? 0X04
????? MOVWF?? TXSTA
????? BCF?? STATUS，RP0
????? MOVLW?? 0X80??????????? ；串行口使能
????? MOVWF?? RCSTA
????? MOVLW?? 0X30
????? MOVWF?? FSR
????? BSF????? RCSTA，CREN????? ；接收允許
????? BSF????? STATUS，RP0
????? BSF????? TXSTA，TXEN????? ；發(fā)送允許
????? BCF????? STATUS，RP0
WAIT?? BTFSS?? PIR1，RCIF????? ；接收PC機(jī)命令
????? GOTO?? WAIT
????? MOVF?? RCREG，0
????? MOVWF?? TEMP
????? MOVWF?? INDF
????? INCF?? FSR
????? DECFSZ?? TEMP???????? ；接收到的數(shù)據(jù)為1，則接收
????? GOTO?? TXW??????????? ；否則發(fā)送數(shù)據(jù)
????? MOVLW?? 0X06
????? MOVWF?? TEMP
WAIT1?? BTFSS?? PIR1，RCIF????? ；接收一個(gè)數(shù)據(jù)
????? GOTO?? WAIT1
????? MOVF?? RCREG，0
????? MOVWF?? COUNT
????? MOVWF?? TXREG
LOOPTX?? BTFSS?? PIR1，TXIF????? ；將接收到的數(shù)據(jù)送回PC機(jī)
????? GOTO?? LOOPTX
????? MOVF?? COUNT，0
????? MOVWF?? INDF??
????? INCF????? FSR
????? DECFSZ?? TEMP
????? GOTO?? WAIT1
????? GOTO?? OVER???????? ；處理完畢
TXW????? MOVLW?? 0X09??????????? ；向PC機(jī)發(fā)送9個(gè)數(shù)據(jù)
????? MOVWF?? TEMP
????? MOVLW?? 0X30
????? MOVWF?? FSR
TXW0?? MOVF?? INDF，0
????? MOVWF?? TXREG
????? INCF????? FSR
TXW1?? BTFSS?? PIR1，TXIF
????? GOTO?? TXW1
????? DECFSZ?? TEMP
????? GOTO?? TXW0??
OVER?? BCF????? RCSTA，CREN????? ；通信任務(wù)完成，關(guān)接受和發(fā)送允許
????? BSF????? STATUS，RP0
????? BCF????? TXSTA，TXEN
????? BCF????? STATUS，RP0
????? CALL?? LED??????????? ；調(diào)用顯示子程序，將發(fā)送（或接收）的數(shù)據(jù)顯示出來(lái)
????? END????????????????? ；程序完
P C 機(jī) 程 序
PC采用Toubr C 進(jìn)行編寫。程序如下：
#include
#define? port??? 0x3f8?????????????? /*利用串口1進(jìn)行通信*/
int ch[15];
main ()
{
?int a;
?int i,j;
?int b[6]={88,15,38,26,20,0};
?char c;
?clrscr();
?outportb(port+3,0x80);?????????????? /*準(zhǔn)備設(shè)置波特率*/
?outportb(port,0x0C);?????????????? /*波特率設(shè)置為9 600 bps*/
?outportb(port+1,0x00);
?outportb(port+3,0x03);?????????????? /*8位數(shù)據(jù)位，奇偶檢驗(yàn)，1位停止位*/
?outportb(port+1,0x00);?????????????? /*關(guān)中斷*/
?inportb(port+5);????????????????? /*讀一次線路狀態(tài)寄存器，使其復(fù)位*/
?{
? printf("\t\tsend data or receive data: (s or r?)\n\n\n");
? c=getchar();
?? switch(c)
?? {
?? case 's':
?? case 'S':
?? {
?? while(!(inportb(port+5)&0x20));???????? /*發(fā)送保持器滿則等待*/
??? outportb(port,0x01);??????????? /*否則發(fā)送數(shù)據(jù)01通知單片機(jī)準(zhǔn)備接收*/
??? for(i=0;i<6;i++)?????????????? /*共發(fā)送6個(gè)數(shù)據(jù)*/
?? {
??? a=b[i];
??? while(!(inportb(port+5)&0x20))
??? delay(100);????????????????? /*發(fā)送保持器滿，等待*/
??? outportb(port,a);?????????????? /*發(fā)送a*/
??? printf("%d\n",a);?????????????? /*顯示a*/
??? while(!(inport(port+5)&1));???????? /*接收單片機(jī)送回的數(shù)據(jù)*/
??? ch[i]=inport(port);?????????????? /*保存*/
??? }
??? delay(10);
??? for(j=0;j<8;j++)?????????????? /*顯示接收的回送數(shù)據(jù)*/
??? printf("\n%d\n",ch[j]);
??? getch();
??? break;
??? }
??? case'r':???????????????????? /*接收數(shù)據(jù)*/
??? case'R':
??? {
???? while(!(inportb(port+5)&0x20));?????
???? outportb(port,0x02);??????????? /*發(fā)送數(shù)據(jù)02通知單片機(jī)發(fā)送數(shù)據(jù)*/
???? for(j=0;j<9;j++)?????????????? /*共接收9個(gè)數(shù)據(jù)*/
???? {
????? while(!(inportb(port+5)&1));
???? ch[j]=inportb(port);
???? }
???? for(j=0;j<9;j++)
???? printf("\n %d\n",ch[j]);
???? getch();
???? break;
???? }
??? }
? }
}
非常好我支持^.^
(2) 100%
不好我反對(duì)
(0) 0%